প্রশ্নঃ বাস্তব সংখ্যায় |2x-3|≤ 1 অসমতাটির সমাধান
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ক.1 < x < 2
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খ.x ≤ 1 অথবা x < 2
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গ.-x < 1 < 2
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ঘ.1 ≤ x ≤ 2
উত্তরঃ ঘ
 1 < x < 2 খ) x ≤ 1 অথবা x < 2 গ) -x < 1 < 2 ঘ) 1 ≤ x ≤ 2 উত্তর: ঘ) 1 ≤ x ≤ 2
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