প্রশ্নঃ
x3 - x2 - 3x - 9, x3 - 2x2 - 2x - 3 এর ল.সা.গু. কত?
-
ক.
(x - 3) (x2 + 2x + 3) (x2 + x + 1)
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খ.
(x - 3) (x2 - x + 3)
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গ.
(x - 3) (x2 + 2x + 3)
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ঘ.
(x - 3) (x2 + x + 3)
উত্তরঃ ক
 (x - 3) (x2 + 2x + 3) (x2 + x + 1) খ) (x - 3) (x2 - x + 3) গ) (x - 3) (x2 + 2x + 3) ঘ) (x - 3) (x2 + x + 3) উত্তর: ক) (x - 3) (x2 + 2x + 3) (x2 + x + 1)
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